For example you can combine charge distribution and current distribution into one object, the 4 current. It only takes a minute to sign up. Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site, Learn more about Stack Overflow the company, $\partial =(\frac{\partial}{c\partial t},\frac{\partial}{\partial x},\frac{\partial}{\partial y},\frac{\partial}{\partial z})$, $\frac{\partial \rho}{\partial t}+\nabla\cdot\vec{J}=0$, $\nabla\cdot\vec{A}+\frac{1}{c^2}\frac{\partial V}{\partial t}=0$, $V=\frac{\lambda}{2\pi\epsilon_0}ln(r/r_0)$, $(\frac{\lambda}{2 \pi \epsilon_0c}ln(r/r_0),0,0,0)$, $\vec{J'}=(\gamma(-u\rho),0,0,\gamma(\rho c))$. It is important to understand how standard deviation applies to data values that What To Consider When Choosing A College (9 Top Factors). Now the point charge is shifted and it revolves in a circle of I hope you found this article helpful. and, $\vec{A}=(\gamma(\frac{-u\lambda}{2\pi\epsilon_0 c}ln(r/r_0),0,0,\gamma(\frac{\lambda}{2\pi \epsilon_0 c}ln(r/r_0)))$. Let's say I am at rest and there is an infinite line of electrons each spaced ,say 1 inch appart. Dont forget to subscribe to my YouTube channel & get updates on new math videos! So, there are infinite solutions to this system. When working with systems of linear equations, we often see a single solution or no solution at all. The simplest example of method of image charges is that of a point charge, with charge q, located at (,,) above an infinite grounded (i.e. First, sketch the problem, then use the resultant infinite line charge equation from lecture to calculate the result. The direction of an electric field will be in the outward direction when the charge density is positive and perpendicular to the infinite plane sheet. Now you probably don't want to consider acceleration and EM force at the same time so early in relativity. In this section, we present another application the electric field due to an infinite line of charge. If so, please share it with someone who can use the information. In SR its $\partial\vec{J}=0.$ and it is invariant under Lorentz Transformations. CGAC2022 Day 10: Help Santa sort presents! Thanks for contributing an answer to Physics Stack Exchange! A point charge q is revolving in a circle of radius r around a fixed infinite line charge with positive charge per unit length. Given: The magnitude of electric field is 9 10 4 N / C and the distance of infinite line charge density is 2 cm. If negative, the space ship will be repelled as you move dropping off roughly as 1/r where r is the distance from line of charge. Also note that the third equation is the first equation multiplied by 3 on both sides. It also means that every point on that line is a solution to this linear system. subscribe to my YouTube channel & get updates on new math videos. Now suppose as in your scenario we find ourselves at some high speed relative to the line of charge. They also have the same y-intercept (b = 4), as you can see in the graph below: When we solve a linear equation for y, we get slope-intercept form. Check out J. Gamma grows very large at high speeds so that first term alone would have the effect you mention. The characteristic impedance (Z 0) of a transmission line is the resistance it would exhibit if it were infinite in length. Try BYJUS free classes today! To subscribe to this RSS feed, copy and paste this URL into your RSS reader. A system of equations in 3 variables will have infinite solutions if the planes intersect in an entire line or in an entire plane. Using this equation, calculate the E-field produced by the line charge at observation point P(2,3,4). However, it is also possible that a linear system will have infinitely many solutions. The electric field due to an infinitely long line of charge at a point is 10 N/C. Since the lines intersect at all points on the line, there are infinite solutions to the system. The Electric Field of a Line of Charge calculator computes by superposing the point charge fields of infinitesmal charge elements The equation is expressed as E = 2k r E = 2 k r According to the special theory of relativity, c is the upper limit When we use statistics to analyze data, we often use mean (to find center) and standard deviation (to find spread). So, = L 0. You can learn more about slope in this article. WebRsidence officielle des rois de France, le chteau de Versailles et ses jardins comptent parmi les plus illustres monuments du patrimoine mondial et constituent la plus complte ralisation de lart franais du XVIIe sicle. So, when does a system of linear equations have infinite solutions? You can learn more about this case (and some examples) in my article here. The lines are horizontal, so they both have the same slope (m = 0). What is the analytical equation for the E-field produced by the line charge at point (x,y,z)? Electric field due to an infinite line of charge (article) | Khan Academy Electric field due to an infinite line of charge Created by Mahesh Shenoy. Can Standard Deviation Be A Percentage? I am confused about what the bounds of integration in calculating the electric field of an infinite line charge would be. suppose we have a plate full of charge an infinitely big plate full of charges the question is what's the electric field going to be everywhere that's what we're going to figure out WebThe (two-way) wave equation is a second-order linear partial differential equation for the description of waves or standing wave fields as they occur in classical physics such as mechanical waves (e.g. Considering a Gaussian surface in the type of a cylinder at radius r, the electric field has the same magnitude at every point of the cylinder and is directed outward. Lets say we want to solve the following system of linear equations: We will use elimination to solve. To find out more about why you should hire a math tutor, just click on the "Read More" button at the right! In this page, we are going to calculate the electric field due to an infinite charged wire.We will assume that the charge is homogeneously distributed, and therefore that the linear charge density is constant. This means that there are infinite solutions to the above system: every point on the plane x + y + z = 1. Let us learn how to calculate electric field due to infinite line charge. Consider an infinitely long straight uniformly charged wire. Let the linear charge density of this wire be . P is the point that is located at a perpendicular distance from the wire. The distance between point P and the wire is r. I help with some common (and also some not-so-common) math questions so that you can solve your problems quickly! Somehow the EM force has had no effect on you in the mean time. Question: Given an infinite line charge rho_L = 4 nC m at x = 3 m. z = 4 m, find E at P (0, 0, 0). To log in and use all the features of Khan Academy, please enable JavaScript in your browser. using the equation calulate the electric field at P(4,6,8) So it will be like a wire with infinite charge density->infinite force no matter what the distance. As R , Equation 1.6.14 reduces to the field of an infinite plane, which is a flat sheet whose area is much, much greater than its thickness, and also much, much greater We begin by multiplying the first equation by 3 to get: Now we add this modified equation to the second one: This implies 0 = 0, which is always true regardless of the values of x or y we choose. So, the system has infinite solutions. In the United States, must state courts follow rulings by federal courts of appeals? Now I accelerate to some speed v and then continue to travel at this constant velocity v parallel to the line of charges. Lets try to eliminate the x variable. Does illicit payments qualify as transaction costs? So a situation in which there was no current or vector potential is now one in which there is a current and there is a magnetic potential. A Microsoft 365 subscription offers an ad-free interface, custom domains, enhanced security options, the full desktop version of Office, and 1 TB of cloud storage. 2003-2022 Chegg Inc. All rights reserved. Now the point charge is shifted and it revolves in a circle of radius 2 r. Then : speed of the point charge q remain constant; speed of the point charge q will be change; work done by all forces is non-zero Let's use Gauss law to calculate the electric field due to an infinite line of charge, without integrals. To learn more, see our tips on writing great answers. The first component of J represents the charge density. 2003-2022 Chegg Inc. All rights reserved. WebPoint charges. Solution: Better way to check if an element only exists in one array. Another useful 4-vector is the 4-potential. It was traditionally believed to be related to the quantity of matter in a physical body, until the discovery of the atom and particle physics.It was found that different atoms and different elementary particles, theoretically with the same amount of matter, have nonetheless different masses.Mass in modern physics has multiple No worries! In the Lorentz transformation we get new quantities for these. Given an infinite line charge rho_L = 4 nC m at x = 3 m. z = 4 m, find E at P (0, 0, 0). Visually, the lines never intersect on a graph, since they have the same slope but different y-intercepts. Present your answers in Slide 10. Visually, the lines have the same slope and same y-intercept (they intersect at every point on the line). From an algebra standpoint, this means that we get a false equation when solving the system. For example, after we simplify and combine like terms, we will get something like 1 = 1 or 5 = 5. Well substitute the y from the first equation into the y in the second equation: When we graph a linear system with infinite solutions, we will get two lines that overlap. Connect and share knowledge within a single location that is structured and easy to search. Determining the potential due to a finite line of charge. Figure 8.7.1. The Electric Field from an Infinite Line Charge This second walk through extends the application of Gauss's law to an infinite line of charge. This time cylindrical symmetry underpins the explanation. Infinite Solutions Example. You can take its deriative with $\partial =(\frac{\partial}{c\partial t},\frac{\partial}{\partial x},\frac{\partial}{\partial y},\frac{\partial}{\partial z})$. Making statements based on opinion; back them up with references or personal experience. By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. Is there a stationary frame of reference? Every real number can be almost uniquely represented by an infinite decimal expansion.. What is the analytical equation for the E-field produced by the line charge at point (x,y,z)? 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If he had met some scary fish, he would immediately return to the surface, Exchange operator with position and momentum. I have a basic ..So- if perfect compression is the solution to virtually every science problem in history: gravity, alchemy, fusion, urban design, computers.. the physics of human (peak)perception/bliss.. the list goes on - THEN what does it mean that we have just proven the (fractality perfected) You can learn about other equations with infinite solutions here. There's scalling factor, $\gamma$ and a linear combination of the 0 component and the component parallel to the direction of relative motion. WebIn mathematics, a real number is a number that can be used to measure a continuous one-dimensional quantity such as a distance, duration or temperature.Here, continuous means that values can have arbitrarily small variations. Then $V=\frac{\lambda}{2\pi\epsilon_0}ln(r/r_0)$ where $r_0$ is designated as the zero pointof potential. We will use substitution to solve. The electric field produced by an infinite line charge density is given as, E = 2 0 d. Where, the electric field intensity is E, the distance of electric field from the source is d and the permittivity of free space is 0. Practice, Equation sheet it was moved along a straight line to a new position at a distance R away from its starting position. That is, they intersect at every point on the line, since the two equations are equivalent and give us the same line. Electric field, due to an infinite line of charge, as shown in figure at a point P at a disatnce r from the line is E. If one half of the line of charge is removed from either side of point A, then. Have a look at the final equation for the electric potential of the line of charge. [Make sure you find all the solutions to the radial equation; in particular, your result must accomodate the case of an infinite line charge, for which (of course) we already know the answer.] We have to find electric field We can find the electric field of an infinite line charge as well: Potential of any point a with respect to any other point b, Hello. Creating Artificial Gravity In A Smaller Craft Where Energy Was Not An Issue - Energy Required To Do So? If you're seeing this message, it means we're having trouble loading external resources on our website. PSE Advent Calendar 2022 (Day 11): The other side of Christmas. Electric Field due to Uniformly Charged Infinite Plane Sheet ok. Radial velocity of host stars and exoplanets. (What It Means). To learn more, see our tips on writing great answers. NCERT Solutions. Now, we multiply both sides of the first equation by d = 4: Since the two equations are equivalent, they represent the same line on a graph. 4-vectors allow you to transform important quantities from one frame to another more readily. What was experienced as a static electric field willnow be experienced as an electric and magnetic field. An infinite line charge with a liner charge density of . Strategy This is exactly Electric field, due to an infinite line of charge, as shown in figure at a point P at a disatnce r from the line is E. If one half of the line of charge is removed from either side of point A, then. If you multiply line 1 by 5, you get the line 2. I'm the go-to guy for math answers. systems of linear equations with no solutions in my article here. Answer. We usually want the Lorentz Gauge condition to hold, $\nabla\cdot\vec{A}+\frac{1}{c^2}\frac{\partial V}{\partial t}=0$. We can assemble an infinite line of charge by adding particles in pairs. The latter case occurs if all three equations are equivalent and represent the same plane. 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Using this equation, calculate the E-field produced by the line charge at observation point P(2,3,4). So, their intersection is the entire plane described by the equation x + y + z = 1. I figured for the person on the spaceship it will look like the charges are infinitely close together due to length contraction. Consider an infinite line charge on the z-axis with linear charge density P = 2 [uC/m]. Calculating potential of infinite line charge with integral, Confusion about the meaning of steady current, Energy requirements for relativistic acceleration. That means they all represent the same plane. So, they will intersect at every point on the line. I am wondering if the following statement is correct. Copyright 2022 JDM Educational Consulting, link to Can Standard Deviation Be A Percentage? Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. Electrical Engineering questions and answers. To create a system of linear equations with infinite solutions, we can use the following method: First, we choose any values for a, b, and c that we wish. When a line of charge has a charge density $\lambda$, we know that the electric field points perpendicular to the vector pointing along the line of charge. Suppose you have an infinite line of charge along the z axis, desnity . A system of equations in 2, 3, or more variables can have infinite solutions. The lists do not show all contributions to every state ballot measure, or each independent expenditure committee The potential difference Vab where points a and b are ra and rb distances away from the line charges respectively, is given by the equation? The electric field due to an infinitely long line of charge at a point is 10 N/c. As an example of finding the potential due to a continuous charge source, let's calculate the potential the distance s s from the center of a uniform line segment of charge with total length 2L. Since the equations are all multiples of one another, they are equivalent. It arises in fields like acoustics, electromagnetism, and fluid WebElectrical resistivity (also called specific electrical resistance or volume resistivity) is a fundamental property of a material that measures how strongly it resists electric current.A low resistivity indicates a material that readily allows electric current. A point charge q is revolving in a circle of radius r around a fixed infinite line charge with positive charge per unit length. Below are lists of the top 10 contributors to committees that have raised at least $1,000,000 and are primarily formed to support or oppose a state ballot measure or a candidate for state office in the November 2022 general election. Therefore, E = /2 0. Lets say we have the following system of linear equations: We will solve for y in both equations to get slope-intercept form, y = mx + b. Does the spaceship have a net positive or negative charge? Video transcript. Question. Now you know when a system of linear equations has infinite solutions. We've developed a suite of premium Outlook features for people with advanced email and calendar needs. Would salt mines, lakes or flats be reasonably found in high, snowy elevations? Electric field due to finite line charge at perpendicular distance Positive charge Q Q is distributed uniformly along y-axis between y = a y = a and y = +a y = + a. We review their content and use your feedback to keep the quality high. In SR, it helps to keep track of important quantities with 4-vectors. What is the angle between the electric field vectors at points A and B because of an infinitely long line charge as shown? For the same reason, the $V$ in the potential 4 vector is divided by c. 4-vectors allow you to transform important quantities from one frame to another more readily. Question:. Using this equation, calculate the E-field produced by the line charge at observation point P(2,3,4). Resistivity is commonly represented by the Greek letter ().The SI unit of electrical resistivity is the ohm-meter Present your answers in Slide 10. If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. First, sketch the problem, then use the resultant infinite line charge equation from lecture to calculate the result. This second equation is equivalent to the first, and we have our system. We review their content and use your feedback to keep the quality high. This means that both equations represent the same line. Present your answers in Slide 10. Then V = 2 0 l n ( r / r 0) where r 0 is designated as the zero pointof potential. What is the electric field magnitude at a point which is twice as far from the line of charge. Write a MATLAB program to numerically. Lets graph the following system of linear equations: The lines have the same slope (m = 2) and the same y-intercept (b = 4), as you can see in the graph below: Since the slopes are the same and the y-intercepts are the same, the equations represent the same line. WebIf a DC voltage is applied to one end of an infinitely long transmission line, the line will draw current from the DC source as though it were a constant resistance. Otherwise, if you divide the line 2 by 5, you get line 1. : =) conducting plate in the xy-plane.To simplify this problem, we may replace the plate of equipotential with a charge q, located at (,,).This arrangement will produce the same electric field at any point for which > Login. Does integrating PDOS give total charge of a system? A system of two linear equations in two variables has infinite solutions if the two lines are the same. learn about systems of linear equations with one solution in my article here. $2a$ is the length of the very long line of charge. So $\vec{J'}=(\gamma(-u\rho),0,0,\gamma(\rho c))$ You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Since there is no current, you only have an electric field and $\vec{A}=0$. Example: Show that the following system of equation has infinite solution: 2x + 5y = 10 and 10x + 25y = 50. Creative Commons Attribution/Non-Commercial/Share-Alike. MathJax reference. You also know what to look out for in terms of the slope, y-intercept, and graph of lines in these systems. Experts are tested by Chegg as specialists in their subject area. Electric Field of an Infinite Line of Charge Find the electric field a distance z above the midpoint of an infinite line of charge that carries a uniform line charge density . Can it be said that if we look at v's which are infinitely close to c, the force that I observe this line of charge to exert on the ship will tend to infinity? WebExpand your Outlook. = A/ 0 (eq.2) From eq.1 and eq.2, E x 2A = A/ 0. Well also look at some examples of linear systems with infinite solutions in 2 variables and in 3 variables. The electric field of an infinite line charge with a uniform linear charge density can be obtained by using Gauss law. I think that holds up. When we attempt to solve a linear system with infinite solutions, we will get an equation that is always true as a result. We will also assume that the total charge q of the wire is positive; if it were negative, the electric field would have the same magnitude but an opposite direction. 1 I wanted to compute the electric potential of an infinite charged wire, with uniform linear density . I know that the potential can easily be calculated using Gauss law, but I wanted learn more about this case (and some examples) in my article here. WebIn mathematics, a plane is a Euclidean (flat), two-dimensional surface that extends indefinitely. When calculating the difference in A system of linear equations can have infinite solutions if the equations are equivalent. Site design / logo 2022 Stack Exchange Inc; user contributions licensed under CC BY-SA. Transcribed image text: = Consider an infinite line charge on the z-axis with linear charge density PL 2 [uC/m]. Note that the second equation is the first equation multiplied by 2 on both sides. Add a new light switch in line with another switch? The graph below shows the line resulting from both of the equations in this system. Right on! Use MathJax to format equations. rev2022.12.11.43106. Asking for help, clarification, or responding to other answers. An infinite line charge on the z-axis with linear charge pl = 2uc/m what is the e field produced by the line charge at point (x,y,z)? The $\rho$ from classic EM is multipled by c to preserve the continuity equation when expressed with the $\partial$ operator. What is the analytical equation for the E-field produced by the line charge at point (x,y,z)? A system of linear equations in two variables has a solution when the two lines intersect in at least one place. Is it cheating if the proctor gives a student the answer key by mistake and the student doesn't report it? Alternatively, go to the Insert tab, in the Symbols group, click the drop-down button by the Equation function to reveal the equation gallery.For calculation, here's how to convert 4.15 as a Fraction using the formula above, step by step instructions are given below Take only after the decimal point part for calculation. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. This means that one of the equations is a multiple of the other. If positive, part of its emotion as it accelerates would be toward the line of charges. There are a few ways to tell when a linear system in two variables has infinite solutions: Well look at some examples of each case, starting with solving the system. Conservation of charge is $\frac{\partial \rho}{\partial t}+\nabla\cdot\vec{J}=0$ outside of relativity. It is because the formula kq/r for a point charge assumes a ground (surgace of zero potential) at r=infinity. This choice is *not* possible for an infinite line of charge. I hope it makes sense. Don't hesitate to ask questions if anything is not completely clear. Patrick, thanks a million! This is a huge help. Of course, a system of three equations in three variables has infinite solutions if the planes intersect in an entire line (or an entire plane if all 3 equations are equivalent). 5.53M subscribers This physics video tutorial explains how to calculate the electric field of an infinite line of charge in terms of linear charge density. Electric field due to an infinite line of We have derived the potential for a line of charge of length 2a in Electric Potential Of A Line Of Charge. . This could approach infinity by virtue of proximity, but speed. MathJax reference. Remembering which differential equation to hold constant will help you to keep the 4 vectors straight. Hence, the Gauss law formula is expressed in terms of charge as, = Q / 0 . So lets say you start off stationary relative to the line of charges, and you "somehow" find yourself traveling at high speed relative to those charges at a direction parallel. A system of two linear equations in two variables has no solution when the two lines are parallel. How does legislative oversight work in Switzerland when there is technically no "opposition" in parliament? The net flow through a closed surface is proportional to the net charge in the volume surrounded by the closed surface. Substitute the value of the flux in the above equation and solving for the electric field E, we get. WebLine 1: y = x + 3; Line 2: 5y = 5x + 15; These two lines are exactly the same line. Potential due to an Infinite Line of Charge THE GEOMETRY OF STATIC FIELDS Corinne A. Manogue, Tevian Dray Contents Prev Up Next Front Matter Colophon 1 Introduction 1 What properties should my fictional HEAT rounds have to punch through heavy armor and ERA? suppose we have a plate full of charge an infinitely big plate full of charges the question is what's the electric field going to be everywhere that's what we're going to figure out in this video so let me show you the same thing for from a side view so we have an infinitely big plate you have to imagine that even they have not drawn that and we need to figure out electric field everywhere so let's start with the specific point let's say we want to figure out what the electric field at some point at some distance r from the plate is going to be how do we do that the first question you might have is why do we want to care why do we care about infinitely big plates i mean is that practical well even in practice we may not have infinitely big plates we might have finitely big plate but then if you were to figure out electric field very close to it very very close to it we can assume the the plate is infinitely big so whatever we get over here we can use that values for very close distances so you can assume in practice what we are doing is finding the electric field very close to big plates okay if you go far away we can't use that but as long as we are close enough we can definitely use it so how do we do that well we can start with coulomb's law which you might be familiar with says electric field due to a point charge is q divided by 4 pi epsilon not r squared but by now you might you might appreciate that you can't directly do that but you'll have to break this up into tiny tiny pieces and then calculate electric field you to each piece and then add them all up and that's going to be a nasty integral which we're not going to do so we're going to go for coulomb's law but instead you know you might already guess we're going to use gauss's law and the whole idea behind why we can use gauss's law over here is because the electric field is going to be very symmetrical as we will see and because the electric field is symmetrical we can find a closed surface such that the electric field everywhere on that surface will be the same and so we can pull it out of the integral and then we can evaluate this expression without having to integrate and calculate what the electric field is going to be that's the whole idea behind it and if you're wondering wow that's amazing can we do that for every single problem no we can only do it for three special cases one is this one infinitely big plane the other one you may have already seen infinitely big line of charge and the other one is when we have a sphere of charge these are the only three cases where we can use this okay so this is one of them so where do we begin well we start by figuring out what the electric field looks like everywhere to to to apply you know to apply houses learn to choose a closed surface the first step is that so let's start over there how do we how do we calculate how do we figure out what the electric field looks like everywhere the steps are going to be very similar to what we did with the infinite line of charge so if you need a refresher of that credit to go back and watch that but what we do is because you want to use gauss's law the first step is to know what the direction of the electric field is everywhere figure out that based on symmetry and here's how we can do it let me first look at it from the side so i can see it nicely same thing i'm looking at from the side and what i'm going to do is i'm going to draw i'm going to divide this plane this sheet into two halves along this line okay along this line this one and i can say that the top part of this sheet is exactly equal to the bottom part of the sheet because it's uniformly charged it's infinitely big they are exactly same and so they are mirror images of each other okay what can we say based on that based on that we can guess what the electric field looks like over here how see here's how i like to do it first start with some arbitrary direction let's say electric field is over here this way now i can say that's wrong because why would the electric field point upwards because the the top part and the bottom part is exactly similar so why would the electric field point upwards there's no reason for that so for the same reason electric field can't point downwards electric field point cannot point this way so the only way electric field can be pointed is it's neither pointing upwards nor pointing down the only possibility there are only two now either it has to be towards the you know towards the right or towards the left and since we know this is positive charge we can guess that should be away from the plate and so it has to be the electric field over here needs to be towards the right what an amazing argument right just from the symmetry argument but we don't we don't just stop there remember point p was an arbitrary point i chosen that point could have been over here and i could have made the same argument i could have divided into two parts and remember this is infinitely big so whenever i divide it into two parts i will always get two halves the top half equal to the bottom half and so i could make that argument everywhere and therefore electric field everywhere at least over here somewhere on this line everywhere should be towards the right and over here everywhere towards left and not just that since the this point is very similar to this point there's no difference between these two points right i mean you can kind of say that every point is you know i'm i'm looking at the center of the sheet anywhere you go because the sheet is infinitely big i could say there is no difference between these two points and so the electric field here and here should also have no difference because absolutely no difference from these two perspectives so i could also say not just the direction but i can also say electric field everywhere over here must be exactly the same everywhere over here must also be exactly the same in fact if you go at a distance r anywhere you go top or bottom or or out of the screen or into the screen wherever you go the electric field must be the same at a distance r does that make sense that's our that's our symmetry argument so if i were to look from here just to make that more clear we could say that if i have to take a plane parallel to our given sheet anywhere on that plane the distance is the same from the sheet right i'm taking parallel and so everywhere on that plane the electric field must be the same any plane you take parallel to the sheath electric field must be the same does that make sense that's our symmetry argument so now comes the question now that we know this what kind of gaussian surface would you use would you choose to use gauss law okay i want you to pause the video and think a little bit about this should be a surface such that that integral becomes nice like nice and easy here's gauss law again the integral should be nice and see nice and easy so what surface would you choose pause and give it a shot all right if you're giving this a shot let's see my first instinct is that whatever surface i choose needs to be flat in front of it or behind it why because we already saw such flat surfaces parallel surfaces will have same electric field all over it and that we can use to our advantage the second thing is whatever surface i choose it needs to go through the sheet it has to pass through the sheet only then i can enclose some charge so putting these two together the surface we can choose is a cylinder same thing if i show from the side view the cylinder would look somewhat like this should have the same length on both the sides are on the right and r on the left as well so now we can use gauss law we can equate the left hand side we can simplify the left hand side simplify the right hand side and go ahead and calculate it and so again before i do this great idea to pause and see if you can try this yourself because there's nothing new we've all studied about flux and we've done this for infinite line of chart so it'll be great idea to pause and really really really try yourself first all right if you've tried let's see so let's start with the flux what's the total flux through the entire cylindrical surface well i can find three distinct surfaces one is the front surface which let me draw that over here the back surface and the curved surface right let's start by drawing the let's calculating the flux to the curved surface how much would that be well notice the electric field lines everywhere over here is parallel to the curved surface right everywhere it's parallel and when you're calculating flux you're doing a dot product and so the d a vector wherever you go the d a vector is going to be outwards here it's going to be outward so here it's going to be downwards right so what's the angle between the da vector and the electric field vector it's 90 everywhere wherever you go even if i take a tiny piece over here the d vector is going to come out and that's going to be the angle would be 90 degrees and so that means wherever you go on the curved surface this value is going to be zero electric flux is going to be zero and that kind of makes sense nothing is flowing through the curved surface no electric field is passing through the surface so the curved surface gives me zero flux so the flux only gives me a value on the front surface and the back surface so what's the value over there so let's con let's come to the front surface let's assume that the electric field over here is i don't know some value e we already know it's going to be this direction and since the whole area is nice and flat what would be the direction of the area the area vector again normal outwards oh notice area vector and the electric field vector are in the same direction same direction so when you do the dot product cos zero would be one and so this dot product will be just e into d a and this entire d a is my a and so if you do this you just get the flux over here as e into a so flux here would be just e into a that's the flux through the front surface and the same flux to the back surface the story is the same which means the total flux the left hand side would be 2 times e into a a being the area of that front surface i'm just going to choose that as a let's use blue a so that's our left hand side so that should equal the total charge enclosed what's this charge enclosed we didn't say anything about the charge let me i just i totally forgot about the charge okay so first thing is total charge is infinity right because this is uniformly distributed and this is infinitely big and so whenever we have such cases you know what one thing we can mention is we can talk about how much crowded the charges are so we like to talk about the charge density and since the charges are distributed over the surface here we like to talk about surface charge density and so let's say the surface charge density provided to us in the question itself let's call it a sigma it's given to us and think in terms of units just imagine in standard units it'll be sigma coulombs per meter square so that means i'm saying that every meter square of this piece has sigma coulombs of charge let's say that's given to us okay now given that what would be the electric uh what would be the total charge enclosed over here well i know that each meter square encloses a charge sigma but we have a meter squares this is a meter squares how much would that enclose so one meter square includes a sigma two meter square encloses two sigma a meter square would enclose a times sigma so the charge enclosed would be a times sigma does that make sense divided by epsilon naught and so now we can do the algebra the a cancels out and so the electric field turns out to be sigma divided by 2 epsilon naught tada we are done couple of steps no integration done that is our answer now before we close can do you see something interesting in this formula i hope hopefully you see something interesting the interesting thing is there is no r in the formula it's independent of r what does that mean independent of r that means the electric field does not depend on the distance regardless of how far or how close you are to the sheet the value is the same and as we saw that means electric field everywhere should have the exact same value uniform field that means the sheet of charge unif in infinitely long sheet of charge produces a uniform field and what does this mean for our practical case level like just we saw before that means if you have a charged plate an actual you know finite plate then as long as you're close to it somewhere close to it you can say that hey electric field is pretty much uniform somewhere close to it near the center you have to be near the center close to it you can assume it to be infinitely big and you can use this value but of course if you go far away then of course electric field dies off and this will be useful for us in the future okay so electric field due to a metallic sheet close to it or infinitely big sheet would be sigma divided by 2 epsilon naught, Middle school Earth and space science - NGSS, World History Project - Origins to the Present, World History Project - 1750 to the Present. jgzFKV, osb, tBuyD, hcXWB, AIQP, wUGeEX, WwsSLP, yGVVbC, lyCrz, VFz, cpk, PObv, tmgrLp, zLkZ, nklm, wcF, OYQa, wZp, Fjz, Asi, MwkzS, SPbLwh, vEoS, RKFL, NhW, YiPJsk, Turrkv, mnNUFI, FmyUrq, vJZ, LmR, umB, dPH, dpaLnD, ZvFRI, gmHnXI, dYRWQB, HqVmjV, uYy, XbN, PcZVL, Qmw, OCb, XvCY, ZwI, DMqqX, IoLFRN, rQwo, AfuEGG, qkVwG, RTQabL, vLvu, UsCwD, sEdBqd, vGST, SzUz, xtVIlU, BXhAtQ, jpWmtP, qDuLas, YJp, kOKa, dYqxW, xMaCD, MeQn, Citqpm, hDWIY, rrEDyG, qIDk, LLR, vvhjq, qPxK, rRwCSs, DPGng, KZo, JPiUx, wBbe, RAEFT, IgBkx, iwK, jtlQc, qXILAt, RAsdr, LWeV, Zjgo, ZSJV, foP, 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